Question

diameter of human eye lens is 2mm.what will be the minimum distance between two points to resolve them,which are situated at a distance of 50m from the eye.The wavelength of light is 5000A.?

Answer 1

$$\begin{gathered} Angularlimitfortheresolutionofeye,\theta =\frac{\lambda }{d}......\left(1\right) \\ \lambda istheminimumresolutionoftheeyewhentwoobjectsareatadis\tan ceDfromtheeyethen, \\ \theta =\frac{y}{D}.......\left(2\right) \\ From\left(1\right)and\left(2\right),weget \\ y=\frac{\lambda D}{d}=\frac{5000\times {10}^{-10}\times 50}{2\times {10}^{-3}}=1.25cm \end{gathered}$$