dinitrogen and dihydrogen react with each other to produce ammonia according to the reaction
N2 + 3H2 gives 2NH3
(a) calculate the mass of ammonia produced 2 x 103 g of dinitrogen reacts with 1 x 103 g of dihydrogen.
(b) will any of the two reactants remain unreacted?
(c) If yes, which one and what would be its mass?

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Solution

N₂ + 3H₂ -------> 2NH3

1 mol + 3 Mol = 2 moles

No. of Moles of N₂ = 206/28 = 7.35
No. of moles of H₂ = 103/2 = 51.5

From the reaction,
7.35 moles of N₂ will react with (7.35x3) = 22.05 M of H₂

Thus, H₂ is in excess.

a) Mass of N₂ + Mass of H₂= 206 g + (22.05 x2) = 206 + 44.1 = 250 g of ammonia
b) H₂ remains unreacted
c) Mass of unreacted H₂ = (51.5 - 22.05) X 2 = 58.9 g

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