Question

Calculate the pH of the following solutions:

a) 2 g of TlOH dissolved in water to give 2 litre of solution.

b) 0.3 g of Ca(OH)₂ dissolved in water to give 500 mL of solution.

c) 0.3 g of NaOH dissolved in water to give 200 mL of solution.

d) 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.

Answer 1

Formula: W =

1- Equivalent weight of TlOH = 221

W = 2 gm V = 2000 ml N = ?

N = = 0.0004 N

pH = N x α

= 0.004 x 1 = 4 x 10^-3

2- Equivalent weight of Ca(OH)₂ = 37 W = 0.3 gm

V = 500 ml

Normality = = 0.016

pH = N x α

= 0.016 x 1 = 0.016

3- Equivalent weight of NaOH = 40 W = 0.3 gm V = 200ml

Normality = = 0.037

pH = N x α

= 0.037 x 1 = 0.037

4- V₁ =1 ml M₁ = N₁ = 13.6 V₂ = 1000ml N₂ = ?

N₁V₁ = N₂V₂

1 X 13.6 = 1000 X N₂

N₂ = 0.0136

pH = N x α

= 0.0136 x 1 = 0.0136