How does pressure effect the rate of reaction ? what happens when pressure is increased or decreased ?
This question can be answered on the basis of Le Chatelier's Principal.
According to this principal, when a dynamic equilibrium is disturbed, the position of the equilibrium moves to counteract the change.
So, when pressure is increased, the equilibrium will move in such a way that the pressure is reduced. So, it shifts in the direction which has lesser number of gaseous molecules. So for the following reaction,
A (g) + 2 B (g) ↔ C (g) + D (g)
i. If the pressure is increased, the equilibrium shifts towards the forward reaction as number of reactant molecules is more than the number of product molecules.
ii. If the pressure is decreased, the equilibrium will shift in the direction which will increase the pressure. Thus, it will move in the backward direction as more number molecules are there.