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Question
Very Citical !
A 40-watt bulb emits monochromatic yellow light of wavelength 580 nm. Calculate the rate of emission of photons per second.
Very Citical !
A 40-watt bulb emits monochromatic yellow light of wavelength 580 nm. Calculate the rate of emission of photons per second.
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Solution
Power of the bulb = 40 W =40 Js-1
Energy of a photon = hν = hc/λ
=(6.626 x 10-34 J s x 3 x 108 m s-1)/(580×10-9 m)
=3.4272 ×10-19 J
Numbers of photon emitted = 40/(3.4275*10-19) =11.67×1019 s-1
Energy of a photon = hν = hc/λ
=(6.626 x 10-34 J s x 3 x 108 m s-1)/(580×10-9 m)
=3.4272 ×10-19 J
Numbers of photon emitted = 40/(3.4275*10-19) =11.67×1019 s-1
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