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Le Chatelier's Principle for Del N Equals to 0

Peq for NH4...

Question

$P_{e q}$ for $N H_{4} C O O N H_{2 (s)} ⇌ 2 N H_{3 (g)} + C O_{2 (g)}$ at certain temperature is $0.9 a t m$ . Then, partial pressure of Ammonia at equilibrium (in atm):

0.9

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0.81

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0.03

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0.6

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Solution

The correct option is D $0.6$
Total partial pressure $= 3 P$

$3 P = 0.9$

$P = 0.3$

$P N H_{3} = 2 P = 2 (0.3) = 0.6$

Hence, the correct option is $D$

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