equation of a line passes through the point of intersection of 2x+y=5 and z+3y+8=0 and parallel to the line 3x+4y=7 is?

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Solution

Point of intersection of lines y=5-2x and y=(8-x)/3 [There is a typing mistake, x should be there in place of z ]
Equating the two lines, we get
5-2x=(8-x)/3
15-6x=8-x
5x=7
x=7/2
So, y = 5-(2Ã—7)/2=-2
Point of intersection (7/2,-2)
Equation of line parallel to 3x+4y-7=0 is
3x+4y-k=0
It should pass through Point of intersection (7/2,-2)

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