P (4, 2) and Q (-1, 5) are the vertices of parallelogram PQRS and (-3, 2) are the co-ordinates of the point of intersection of its diagonals. Find co-ordinates of R and S.

Q. Find the co-ordinates of the centroid of a triangle whose vertices are

(3, - 5), (- 6, 4)

and

(9, - 8)

Join BYJU'S Learning Program

P≡(1,−9), Q≡(2,5) and R≡(6,7) are the co-ordinates of the vertices of △PQR, then find the co-ordinates of the centroid from the following alternatives given:

The correct option is C (3,1)P≡(1,−9) Q≡(2,5)R≡(6,7)∴ Centroid (x,y)=(1+2+63,−9+5+73)=(93,33)∴ Centroid =(3,1).

$P \equiv (1, - 9)$ , $Q \equiv (2, 5)$ and $R \equiv (6, 7)$ are the co-ordinates of the vertices of $△ P Q R$ , then find the co-ordinates of the centroid from the following alternatives given:

The correct option is C $(3, 1)$
$P \equiv (1, - 9)$
$Q \equiv (2, 5)$
$R \equiv (6, 7)$
$∴$ Centroid $(x, y) = (\frac{1 + 2 + 6}{3}, \frac{- 9 + 5 + 7}{3})$
$= (\frac{9}{3}, \frac{3}{3})$
$∴$ Centroid $= (3, 1)$ .