Question

examine whether (7, 24, 25) form a pythagorean triplet or not. (WITH STEPS)

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{a}=7;\mathrm{b}=24;\mathrm{c}=25 \\ \mathrm{Now},{\mathrm{c}}^2={25}^2=625 \\ {\mathrm{a}}^2+{\mathrm{b}}^2=7^2+{24}^2=49+576=625 \\ \mathrm{since},{\mathrm{c}}^2={\mathrm{a}}^2+{\mathrm{b}}^2,\mathrm{then} \\ \left(\mathrm{a},\mathrm{b},\mathrm{c}\right)\mathrm{form}\mathrm{a}\mathrm{pythagorean}\mathrm{triplet}. \\ \left(7,24,25\right)\mathrm{form}\mathrm{a}\mathrm{pythagorean}\mathrm{triplet}. \end{gathered}$$