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Question

explain about the axial symmetry of potential due to a dipole? i am having problem

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Solution

Potential due to dipole is given by:
V = pcos θ4πεor2where θ is the angle between dipole mment p and position vecor r.Now consider a point p whose position vector is making an angle θ with axial line or diploe moment.If we rotate this point p around axial line at the constant angle θ, then it will trace a cone arond the axial line,which has same potential.This is called the axial symmetry of potential due to dipole.

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