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1 - justify and explain d orbitals splitting is inverted and is smaller as compare to octahedral field splitting

2 - how dd transition helps in deciding the colour of complex

3 - explain instability constant and compile complexand labile complex

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Solution

1) In tetrahedral field d orbital splitting is inverted and smaller because none of the d orbitals in tetrahedral field point exactly to the ligand.But dxy,dyz,dzx approach ligand more closely as compared to that of dz2 and dx2-y2 .Therefore for a tetrahedron splitting of d orbitals is inverted and smaller.

2)In a d–d transition, an electron in a d orbital on the metal is excited by a photon to another d orbital of higher energy. In complexes of the transition metals, the d orbitals do not all have the same energy.As we know about the d orbital splitting.
Thus when an electron in lower energy d orbital absorbs radiation of certain wavelength it gets excited to the higher energy d orbital and the characteristic color is the complementary to the colour of the absorbed radiation.
3) Its Stability constant not Instabilty constant i guess.
Stability constant is the equilibrium constant for the formation of coordination complex in a solution.
Labile complexes : for which the dissociation constant is very high and thus are unstable.
Compile colexes are basically inert complexes for which the stability is high that is they do not dissociate easily.


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