Question

Express tanθ in terms of cosθ.

Answer 1

$$\begin{gathered} \tan \theta =\frac{\sin \theta }{\cos \theta } \\ \mathrm{Now},\mathrm{we}\mathrm{know}\sin \theta =\sqrt{1-{\cos }^2\theta } \\ \mathrm{Thus},\tan \theta \mathit{}=\frac{\sqrt{1-{\cos }^2\mathrm{\theta }}}{\mathrm{cos\theta }}\left(\mathrm{answer}\right) \end{gathered}$$