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Question

Factorise

(i) a4b4

(ii) p4 − 81

(iii) x4 − (y + z)4

(iv) x4 − (xz)4

(v) a4 − 2a2b2 + b4

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Solution

(i) a4b4 = (a2)2 − (b2)2

= (a2b2) (a2 + b2)

= (ab) (a + b) (a2 + b2)

(ii) p4 − 81 = (p2)2 − (9)2

= (p2 − 9) (p2 + 9)

= [(p)2 − (3)2] (p2 + 9)

= (p − 3) (p + 3) (p2 + 9)

(iii) x4 − (y + z)4 = (x2)2 − [(y +z)2]2

= [x2 − (y + z)2] [x2 + (y + z)2]

= [x − (y + z)][ x + (y + z)] [x2 + (y + z)2]

= (xyz) (x + y + z) [x2 + (y + z)2]

(iv) x4 − (xz)4 = (x2)2 − [(xz)2]2

= [x2 − (xz)2] [x2 + (xz)2]

= [x − (xz)] [x + (xz)] [x2 + (xz)2]

= z(2xz) [x2 + x2 − 2xz + z2]

= z(2xz) (2x2 − 2xz + z2)

(v) a4 − 2a2b2 + b4 = (a2)2 − 2 (a2) (b2) + (b2)2

= (a2 b2)2

= [(ab) (a + b)]2

= (ab)2 (a + b)2


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