Find : 50 + (-40) - (+2) - (-65)

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Solution

50 + (–40) – (+2) – (–65)
= 50 – 40 – 2 + (+65) (Additive inverse of (–65) is (+65))
= 50 – 42 + 65
= 65 + 50 – 42 (Arranging negative and positive integers in groups)
= 115 – 42
= 73

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Similar questions

Q. Find the median :

Weight	No of students
$40 - 45$	$2$
$45 - 50$	$3$
$50 - 55$	$8$
$55 - 60$	$6$
$60 - 65$	$6$
$65 - 70$	$3$
$70 - 75$	$2$

Find the class marks of classes

30 - 35, 35 - 40

and

40 - 45

in the data below:

Marks	Number of student
$30 - 35$	$5$
$35 - 40$	$8$
$40 - 45$	$15$
$45 - 50$	$20$
$50 - 55$	$5$
$55 - 60$	$4$
$60 - 65$	$4$
$65 - 70$	$2$
$70 - 75$	$3$

Q. Draw less than and greater than give then find median

Age	$20 - 25$	$25 - 30$	$30 - 35$	$35 - 40$	$40 - 45$	$45 - 50$	$50 - 55$	$55 - 60$	$60 - 65$	$65 - 70$
Cf	$21$	$40$	$90$	$130$	$146$	$166$	$176$	$186$	$195$	$199$

Q. The marks obtained by

20

students in maths are

35, 40, 78, 30, 50, 78, 36, 65, 78, 40, 30, 65, 50, 35, 80, 95, 80, 36, 95, 35

. Find the Arithmetic mean of the students by direct method.

The distribution below gives the weight of 30 students in a class. Find the median weight of students:
Weight (in kg): 40-45 45-50 50-55 55-60 60-65 65-70 70-75
No. of students: 2 3 8 6 6 3 2

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Find : 50 + (-40) - (+2) - (-65)

50 + (–40) – (+2) – (–65)= 50 – 40 – 2 + (+65) (Additive inverse of (–65) is (+65))= 50 – 42 + 65= 65 + 50 – 42 (Arranging negative and positive integers in groups)= 115 – 42= 73

50 + (–40) – (+2) – (–65)
= 50 – 40 – 2 + (+65) (Additive inverse of (–65) is (+65))
= 50 – 42 + 65
= 65 + 50 – 42 (Arranging negative and positive integers in groups)
= 115 – 42
= 73