find area bounded by y = sin x betn x = 0 n x = 2pi?

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Solution

the required area is $A = \int_{0}^{2 π} |\sin x| d x$
$= 2 \int_{0}^{π} \sin x d x$
$= 2 * [- \cos x |_{0}^{π} = - 2 * [\cos π - \cos 0] = - 2 (- 1 - 1) = - 2 * (- 2) = 4 s q u n i t$

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