Find area enclosed by the curvey= 4xand x axis fromx= 0 tox= 1
4 1 2

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Solution

Dear student
$R e q u i r e d a r e a = \int_{0}^{1} 4 x d x = \frac{4 x^{2}}{2} f r o m x = 0 t o 1 = 2 x^{2} f r o m x = 0 t o 1 = 2 {(1)}^{2} - 2 {(0)}^{2} = 2 s q u n i t s$
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