Find d point which is equidistance from d point A (-5,4) & B (-1,6)? How many such points r there?
Let P(x, y) be the point which is equidistance from the points A(–5, 4) and B(–1, 6).
Then PA = PB
⇒ PA2 = PB2
⇒ (x – (–5))2 + (y – 4)2 = (x – (–1))2 + (y – 6)2
⇒ x2 + 25 + 10x + y2 + 16 – 8y = x2 + 1 + 2x + y2 + 36 – 12y
⇒10x – 2x – 8y + 12y + 41 – 37 = 0
⇒8x + 4y + 4 = 0
⇒2x + y + 1 = 0 .......... (1)
Hence all the point satisfying (1) i.e. lying on line (1) are equidistance from A and B.
There are infinite number of such points.