Question

find the cube root of 21952, 4913 and 9261 by prime factorization.

Answer 1

$$\begin{gathered} \left(\mathbf{a}\right) \\ \sqrt[3]{21952}=\sqrt[3]{2\times 2\times 2\times 2\times 2\times 2\times 7\times 7\times 7} \\ =2\times 2\times 7 \\ =28 \\ \left(\mathbf{b}\right) \\ \sqrt[3]{4913}=\sqrt[3]{17\times 17\times 17} \\ =17 \\ \left(\mathbf{c}\right) \\ \sqrt[3]{9261}=\sqrt[3]{3\times 3\times 3\times 7\times 7\times 7} \\ =3\times 7 \\ =21 \end{gathered}$$