Question

Find the least number which should be subtracted from 19318 so that the difference is exactly divisible by 125.

Answer 1

Firstly divide 19318 by 125 we get;
$$\begin{gathered} 125\left)19318\right(154 \\ 125 \\ \overline{681} \\ 625 \\ \overline{568} \\ 500 \\ \overline{68} \end{gathered}$$
Since the remainder is 68. Therefore the least number subtracted from 19318 is 68.
19318 - 68 = 19250 which is exactly divisible by 125.