find the smallest number which when diminished by 6 is divisible by 12,15,20 and 27.
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Solution
Dear student
The prime factorization of the above number is
12=2x2x3
15=3x5
20=2x2x5
and 27=3x3x3
So, LCM(12,15,20,27)=2x2x3x3x3x5=540
So, Required number is LCM(12,15,20,27)+6=540+6=546
Regards