find the volume, total surface area, lateral surface area and the length of diagonal of a cube, each of whose edges measures 20 cm

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Solution

$S i d e = 20 c m V o l u m e = 20 \times 20 \times 20 = 8000 c m^{3} L . S . A . = 4 (20)^{2} = 4 (400) = 1600 c m^{2} T . S . A = 6 (20)^{2} = 6 (400) = 2400 c m^{2} L e n g t h o f d i a g o n a l = \sqrt{20^{2} + 20^{2}} = \sqrt{2 (20)^{2}} = 20 \sqrt{2} c m$

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find the volume, total surface area, lateral surface area and the length of diagonal of a cube, each of whose edges measures 20 cm

Side = 20 cmVolume = 20×20×20 = 8000 cm3L.S.A. = 4(20)2=4(400) = 1600 cm2T.S.A = 6(20)2 = 6(400) = 2400 cm2Length of diagonal = 202+202=2(20)2=202cm

$S i d e = 20 c m V o l u m e = 20 \times 20 \times 20 = 8000 c m^{3} L . S . A . = 4 (20)^{2} = 4 (400) = 1600 c m^{2} T . S . A = 6 (20)^{2} = 6 (400) = 2400 c m^{2} L e n g t h o f d i a g o n a l = \sqrt{20^{2} + 20^{2}} = \sqrt{2 (20)^{2}} = 20 \sqrt{2} c m$