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Multiplication of Numbers

Find theleast...

Question

Find theleast number which when divided by 6, 15 and 18 leave remainder 5 ineach case.

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Solution

LCM of 6,15, 18

2

6, 15, 18

3

3, 15, 9

3

1, 5, 3

5

1, 5, 1

1, 1, 1

LCM = 2 Ã—3 Ã— 3 Ã— 5 = 90
Requirednumber = 90 + 5 = 95

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