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Question

find three consecutive even numbers such that the sum of the first and the last numbers exceeds the second number by 10.

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Solution

Dear Student!

Let the three consecutive even numbers be x, x + 2 and x + 4.

Given, x + (x + 4) = (x + 2) + 10

∴ 2x + 4 = x + 12

⇒ 2x – x = 12 – 4 (Transposing x on the LHS and 4 on the RHS)

⇒ x = 8

x + 2 = 8 + 2 = 10

x + 4 = 8 + 4 = 12

Thus, the three consecutive even numbers are 8, 10 and 12.

Cheers!


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