-8203-for a reaction A - 2B - C - gt- ABC- the rate law is rate - k -A- -C-2- nbsp- Find nbsp-a- nbsp- Unit of rate constant nbsp-b- Effect on rate of reaction if concentrated of B is doubled-

Dear Student Unit of rate constant = (mol L 1)1 n nbsp;s 1, where n= order of reaction. nbsp; Here order of reactin is = 1+2 = 3 therefore, unit of rat ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Derivation of Kp and Kc

#8203;for a r...

Question

for a reaction A + 2B + C ---> ABC, the rate law is rate = k [A] [C]^2. Find

(a) Unit of rate constant

(b) Effect on rate of reaction if concentrated of B is doubled.

Open in App

Solution

Dear Student

Unit of rate constant = (mol L^-1)^1-n s^-1, where n= order of reaction.
Here order of reactin is = 1+2 = 3
therefore, unit of rate constant = (mol L^-1)^1-3 s^-1= (mol L^-1)^-2 s^-1 = L²mol^-2 s^-1

Change in conc. of B does not effect the rate of reaction because rate law is independent of the term B.

Suggest Corrections

Similar questions

Q. Rate law for the reaction,

A + 2 B \to C

is found to be

R a t e = k [A] [B]

Concentration of reactant 'B' is doubled, keeping the concentration of 'A' constant, the value of rate constant will be ................. .

Q. Rate law for the reaction,

A + 2 B \to C

is found to be,

R a t e = k [A] [B]

The concentration of reactant

^{'} B^{'}

is doubled, keeping the concentration of

^{'} A^{'}

constant, the value of the rate constant will be:

In a reaction, $A + B \to$ Product, rate is doubled when the concentration of B is doubled and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled. Rate law for the reaction can be written as :

A + 2 B \to C

, the rate equation for reaction is given as

R a t e = [A] [B]

. If the concentration of A is kept constant while B is doubled. What will happen to the rate?

Q. For a chemical reaction,

2 A + 2 B \to 2 C

, the rate controlling step is

A + \frac{1}{2} B \to C

. If the concentration of B is doubled, the rate of reaction will:

Join BYJU'S Learning Program

​for a reaction A + 2B + C ---> ABC, the rate law is rate = k [A] [C]^2. Find (a) Unit of rate constant (b) Effect on rate of reaction if concentrated of B is doubled.

for a reaction A + 2B + C ---> ABC, the rate law is rate = k [A] [C]^2. Find

(a) Unit of rate constant

(b) Effect on rate of reaction if concentrated of B is doubled.