Question

P = $\frac{7}{8}$, Q = $\frac{8}{7}$ and R = $\frac{1}{7}$. is the largest among these fractions.

• A. P
• B. Q
• C. R

Answer 1

The correct option is B Q

If we convert all of them into like fractions by LCM method,

i.e., LCM of 8, 7 and 7 will be 56,
So P = $\frac{7\times 7}{8\times 7}$ = $\frac{49}{56}$

Q = $\frac{8\times 8}{7\times 8}$ = $\frac{64}{56}$

and R = $\frac{1\times 8}{7\times 8}$ = $\frac{8}{56}$

We get:

$\frac{64}{56}$ > $\frac{49}{56}$ > $\frac{8}{56}$
Or
Q > P > R

$\therefore$ Q is greater.