Given a triangle with side AB= 8 cm . To get a line segment of AB' = 3/4 of AB , it is required to divide the line segment AB in the ratio :
(A) 3:4
(B) 4:3
(C) 1:3
(D) 3:1

Open in App

Solution

AB is the line segment. AB = 8 cm.
In order of locate B' on AB such that AB' = (3/4) AB, divide the line segment AB in the ratio 3: 4.

Suggest Corrections

Similar questions

Given a triangle with side AB = 8 cm. To get a line segment AB' = ³/₄ of AB, it is required to divide the line segment AB in the ratio:

Points P and Q are in the line segment AB and on the same side of its midpoint. P divides AB in the ratio 2:3 and Q divides AB in the ratio 3:4. If $P Q = 2 c m,$ then find the length of the line segment AB.

Q. Draw a line segment

A B = 8 c m

.Draw

3 / 4

part of it measure the length of 3/4 part of

A B

with picture

Divide a line segment AB of length 9 cm in the ratio 4:4 at C. Now, divide the new line segment AC in the ratio 3:2 at M.

Q. Points P and Q are both in the line segment AB and on the same side of its midpoint. P divides AB in the ratio

2 : 3

, and Q divides AB in the ratio 3:4. If PQ=2, then find the length of the line segment AB.

Join BYJU'S Learning Program

Given a triangle with side AB= 8 cm . To get a line segment of AB' = 3/4 of AB , it is required to divide the line segment AB in the ratio :(A) 3:4(B) 4:3(C) 1:3(D) 3:1

AB is the line segment. AB = 8 cm.In order of locate B' on AB such that AB' = (3/4) AB, divide the line segment AB in the ratio 3: 4.

Given a triangle with side AB= 8 cm . To get a line segment of AB' = 3/4 of AB , it is required to divide the line segment AB in the ratio :
(A) 3:4
(B) 4:3
(C) 1:3
(D) 3:1

AB is the line segment. AB = 8 cm.
In order of locate B' on AB such that AB' = (3/4) AB, divide the line segment AB in the ratio 3: 4.