Given the standard electrode potentials
K+| k = -2.93 V; Ag+|Ag = +0.8V; Mg2+| Mg=-2.37 V
Arrange these metals in order of increasing reducing power.
Given the standard electrode potentials,
K+/K = −2.93V, Ag+/Ag = 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = −2.37 V, Cr3+/Cr = − 0.74V
Arrange these metals in their increasing order of reducing power.
Given the standard electrode potentials, K+/K=−2.93 V,Ag+/Ag=0.80 V,Hg2+/Hg =0.79 V Mg2+/Mg=−2.37V.Cr3+/Cr=−0.74V Arrange these metals in their increasing order of reducing power.