Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximate 67200. The number of iron atoms present in one molecule of haemoglobin are

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Solution

Percentage of Fe = 0.33% molecular weight of haemoglobin
Therefore,
Weight of Fe present = (0.33/100)*67200
= 221.76

Atomic mass of Fe = 56
Number of approximate atoms present = 221.76/56
= 3.96 ~ 4
Hence, there are 4 Fe atoms in one haemoglobin molecule.

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Haemoglobin contains 0.33% of iron by weight . The molecular weight of haemoglobin is approximately 67200 . The number of iron atoms ( at . wt. of Fe=56) present in one molecule of haemoglobin is

Q. Haemoglobin contains 0.334% of iron by weight. The molecular weight of haemoglobin is approximately

67200 amu

. The number of iron atoms (Atomic weight of

F e

is 56) present in one molecule of haemoglobin is:

Q. Haemoglobin contains 0.33% of iron by weight. The molecular mas of haemoglobin is about 67200. the number of iron atoms (atomic mass of Fe=56) present in molecule of haemoglobin is:

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Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximate 67200. The number of iron atoms present in one molecule of haemoglobin are

Percentage of Fe = 0.33% molecular weight of haemoglobin Therefore,Weight of Fe present = (0.33/100)*67200 = 221.76Atomic mass of Fe = 56 Number of approximate atoms present = 221.76/56 = 3.96 ~ 4Hence, there are 4 Fe atoms in one haemoglobin molecule.

Percentage of Fe = 0.33% molecular weight of haemoglobin
Therefore,
Weight of Fe present = (0.33/100)*67200
= 221.76

Atomic mass of Fe = 56
Number of approximate atoms present = 221.76/56
= 3.96 ~ 4
Hence, there are 4 Fe atoms in one haemoglobin molecule.