Question

heat on lead nitrate gives yellow lead[ll] oxide, nitrogen dioxide & ooxygen . calculate the total vol of NITROGEN DIOXIDE and OXYGEN

produced on heating 8.5 of lead nitrate. { PB=207,N=14,O=16}

Answer 1

2Pb(NO₃)_{2 (s)} → 2PbO _(s) +4NO_{2 (g)} + O_{2 (g)}

Molar mass of Pb(NO₃)₂ = 331 g/mol

Molar mass of NO₂ = 46 g/mol

Molar mass of O₂ = 32 g/mol

Now, we know that molar mass of a gas contains 22.4 L of gas so,

46 g of Nitrogen dioxide = 22.4 L

32 g of Oxygen = 22.4 L

According to balanced chemical equation,

(2x331)=662g of lead nitrate yields (4x22.4)=89.6 L of nitrogen dioxide and 22.4 L of oxygen gas.

Total volume of gases = 89.6 + 22.4 = 112 L

662 g of lead nitrate produces 112 L of gases

8.5 g of lead nitrate will produce (112x8.5)/662 = 1.44 L of gases