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Question

HELIUM GAS IS MONOATOMIC . WHAT WILL BE THE MASS OF 6.022 X 1024ATOMS IN HELIUM

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Solution

Given:

Number of atoms in He gas = 6.022 X 1024

Molar mass = 4u

Number of atoms = ( mass / molar mass) * Avogadro number

6.022 X 1024 = ( mass / 4) * 6.022 * 1023

Mass = ( 6.022*1024 / 6.022*1023 ) * 4

= 40g

So. 40g He gas contains 6.022*1024 atoms.


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