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Question

How many atoms are present in 0.5g of atoms of silicon?

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Solution

Atomic mass of silicon is 28 g

So, 28 g of silicon has 6.023 * 1023 atoms

In 0.5 g of silicon, number of atoms of silicon = (6.023*1023 /28) * 0.5 = 1.0755 *1022


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