How many atoms are present in 0.5g of atoms of silicon?
Atomic mass of silicon is 28 g
So, 28 g of silicon has 6.023 * 1023 atoms
In 0.5 g of silicon, number of atoms of silicon = (6.023*1023 /28) * 0.5 = 1.0755 *1022
A silicon chip used in an integrated circuit of a microcomputer has a mass of 5.68mg . How many silicon (Si) atoms are present in this chip