Question

How many atoms are present in 11.2 ltrs of chlorine at STP

Answer 1

At STP
Volume of a gas = 22.4 L/mol
No. of moles of chlorine in 22.4 L = 1 mole

No. of moles of Chlorine in 11.2 L =$\frac{1}{22.4}\times 11.2=\frac{1}{2}moles$ of chlorine

No. of atoms in 1 mole = 6.023 x 10²³ atoms

No. of atoms in 0.5 mole of chlorine = 3.0115 x 10²³ atoms