How many cylindrical iron rods 7 m long and diameter 2 cm can be made out of 0.88 cu. cm of iron.

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Solution

h=7 m = 0.07 cm
Diameter =2 cm
Radius, r = 1 cm
$V o l u m e o f e a c h c y l i n d r i c a l i r o n r o d = {πr}^{2} h = \frac{22}{7} * 1^{2} * 0.07 = 0.22 {cm}^{3}$

Now, 0.88/0.22= 4
So, 4 cylindrical iron rods can be made.

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How many cylindrical iron rods 7 m long and diameter 2 cm can be made out of 0.88 cu. cm of iron.

h=7 m = 0.07 cm Diameter =2 cm Radius, r = 1 cm Volume of each cylindrical iron rod =πr2h=227*12*0.07=0.22 cm3 Now, 0.88/0.22= 4 So, 4 cylindrical iron rods can be made.

h=7 m = 0.07 cm
Diameter =2 cm
Radius, r = 1 cm
$V o l u m e o f e a c h c y l i n d r i c a l i r o n r o d = {πr}^{2} h = \frac{22}{7} * 1^{2} * 0.07 = 0.22 {cm}^{3}$

Now, 0.88/0.22= 4
So, 4 cylindrical iron rods can be made.