How many electrons can be filled in all orbitals with n + l = 5?
How many electrons can be filled in all orbitals with n + l = 5?
There are five orbitals which have the same value of (n + l) = 5. These are the 5s, 4p and 3d orbitals. For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2.
For the 4p orbital, n = 4 and l = 1, therefore (n + l) = 5. As a p subshell has three orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 4p orbital would be 6.
For the 3d orbital, n = 3 and l = 2, therefore (n + l) = 5. As a d subshell has five orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5d orbital would be 10.
There are five orbitals which have the same value of (n + l) = 5. These are the 5s, 4p and 3d orbitals. For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2.
For the 4p orbital, n = 4 and l = 1, therefore (n + l) = 5. As a p subshell has three orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 4p orbital would be 6.
For the 3d orbital, n = 3 and l = 2, therefore (n + l) = 5. As a d subshell has five orbitals and each orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5d orbital would be 10.
