how many ions each of Na+ and Cl- are present in 12.0 g of NaCl

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Solution

Dear student!
We know that, 1 mole of NaCl = 6.022 x 10²³ Na⁺ ions + 6.022 x 10²³ Cl^- ions( due to ionic compound nature)
So, 1 mole of NaCl = 23 + 35.5 = 58.5 gm NaCl
Now 58.5 gm NaCl contains = 6.022 x 10²³ Na⁺ ions
so, 12 gm of NaCl will contain = 6.022 x 10²³ x 12/58.5 Na⁺ ions = 1.23x 10²³ Na⁺ ions
And so, it will have 1.23 x 10²³ Cl^- ions too.

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