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Question

how many isomers are there for the following:

i.butane

ii.pentane

iii.haxane

iv.heptane

v.octane

vi.nonane

vii.decane

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Solution

The general formula for determining the number of isomers of any hydrocarbon is 1+24-n

Where n is the number of carbon present in the molecular formula.

i.butane = 2

ii.pentane = 3

iii.haxane = 5

iv.heptane = 9

v.octane = 17

vi.nonane = 33

vii.decane = 65


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