Question

how many moles of potassium chlorate to be heated to produce 11 2 liters of oxygen

Answer 1

Dear student!

The production of oxygen from per chlorate is as follows:

2KClO₃ (s) -> 2KCl (s) + 3O₂(g)

so, here 2 moles of per chlorate is used to produce 3 moles of oxygen gas.

So, 1 mole of oxygen gas will need = 2/3 moles of per chlorate.

Now we know that 1 mole of oxygen gas at STP = 22.4 L

So, 112 L oxygen gas = 112/22.4 =5 Moles of oxygen gas.

So, 5 moles (112L) of oxygen gas will be produced by = 5 x 2/3 moles of per chlorate = 3.33 moles