How much force is applied on the body when 150joule of work is done in displacing the body through a distance of 10m in the direction of force?

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Solution

Here, W = 150 J
s = 10 m
θ = 0⁰
As W = F s cos θ
Therefore, F = $\frac{W}{s \cos θ} = \frac{150}{10 \times \cos 0^{0}} = \frac{150}{10} = 15 N$

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How much force is applied on the body when 150joule of work is done in displacing the body through a distance of 10m in the direction of force?

Here, W = 150 J s = 10 m θ = 00 As W = F s cos θ Therefore, F = W s cos θ = 15010 × cos 00 = 15010 = 15 N

Here, W = 150 J
s = 10 m
θ = 0⁰
As W = F s cos θ
Therefore, F = $\frac{W}{s \cos θ} = \frac{150}{10 \times \cos 0^{0}} = \frac{150}{10} = 15 N$