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Question

how to find HCF( highest common factor) of 2400, 2800 ,3360?

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Solution

Given numbers can be prime factorized as follows:

2400 = 2 × 2 × 2 × 2 × 2 × 3 × 5 × 5

2800 = 2 × 2 × 2 × 2 × 5 × 5 × 7

3360 = 2 × 2 × 2 × 2 × 2 × 3 × 5 × 7

It can be seen that 2 × 2 × 2 × 2 × 5 is highest common part in all three factorization.

Thus, 2 × 2 × 2 × 2 × 5 = 80 is HCF of given numbers.


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