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Question

how to solve the equations - 2x2 + 7xy + 3y2.

x3 + 7x2y + 16xy2 + 12y3

3x3 - 14x2 + 9x + 10

15x3 - 34x2 + 21x - 10

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Solution

1)
2x2+7xy+3y2=2x2+6xy+xy+3y2=2xx+3y+yx+3y=x+3y2x+y

2)
x3+7x2y+16xy2+12y3By trial and error method we found that when x=3, y=-1 and when x=-3, y=1 x=-3yx+3y is a factor of x3+7x2y+16xy2+12y3Using long division method we getx3+7x2y+16xy2+12y3x+3y x2+4xy+4y2 -x3-3x2y 0+4x2y+16xy2+12y3 -4x2y-12xy2 0+4xy2+12y3 -4xy2-12y3 0x3+7x2y+16xy2+12y3=x+3yx2+4xy+4y2=x+3yx2+2xy+2xy+4y2=x+3yxx+2y+2yx+2y=x+3y x+2y x+2y

3)
3x3-14x2+9x+10Using trial and error method we get that 3x3-14x2+9x+10 =0 when x=533x-5 is a factor of 3x3-14x2+9x+10Using long division we get 3x3-14x2+9x+103x-5 x2-3x-2 -3x3+5x2 0-9x2+9x+10 9x2-15x 0-6x+10 6x-10 03x3-14x2+9x+10=3x-5x2-3x-2Consider x2-3x-2x=-b±b2-4ac2a=3±9+82=3±1722x-3+17 and 2x-3-17 are factors of x2-3x-23x3-14x2+9x+10=3x-52x-3+172x-3-17

4)
15x3-34x2+21x-10Using trial and error method we get that 15x3-34x2+21x-10 =0 when x=533x-5 is a factor of15x3-34x2+21x-10Using long division we get15x3-34x2+21x-103x-5 5x2-3x+2 -15x3+25x2 0-9x2+21x-10 9x2-15x 0+6x-10 -6x+10 015x3-34x2+21x-10=3x-55x2-3x+2

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