How to solve this problem?
Two persons take steps of 64cm and 84cm respectively. If they start in step, how far will they make before they are in step again?

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Solution

Hi!

Here is the answer to your question.

Given, two persons take steps of 64cm and 84cm.
Minimum distance covered by the two persons before they are in steps again = LCM of 64cm and 84 cm
We know that, prime factorization of a natural number is unique.

64 = 2 × 2 × 2 × 2 × 2 × 2

84 = 2 × 2 × 3 × 7

LCM of 64 and 84 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7 = 1344

∴ Minimum distance covered by the two persons before they are in steps again = 1344 cm

Cheers!

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How to solve this problem? Two persons take steps of 64cm and 84cm respectively. If they start in step, how far will they make before they are in step again?

How to solve this problem?
Two persons take steps of 64cm and 84cm respectively. If they start in step, how far will they make before they are in step again?