If A and B are mutually exclusive and exhaustive events what is the probability of A U B

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Solution

P (AUB) = P(A) + P(B) - P(A $\cap$ B).

Given they are mutually exclusive. Hense P (A $\cap$ B) = 0 . Also since it is given that they are exhaustive ,

P (A U B) = n(A U B)/total no of possibilities

= n( A U B)/n(A U B) [ as they are exhaustive]

=1 [certain event.]

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Similar questions

Three coins are tossed. Describe
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(ii) three events A, B and C which are mutually exclusive and exhaustive.

(iii) two events A and B which am not mutually exclusive.

(iv) two events A and B which are mutually exclusive but not exhaustive.

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P (¯ ¯¯ ¯ B)

If A and B are two mutually exclusive and exhaustive events, then $P (B) = 1 - P (A) .$

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