Question

if a conductor of resistance 5 ohm is connected dametrcally n a crcuit. what is the change of resistance?

Answer 1

As per question, a conductor having resistance 5 ohm is connected diametrically, that is resistance of the conductor get divided into two semicircles and on bending they are assumed to be connected in parallel. Thus, the net change in the resistance or the equivalent resistance of the circuit becomes,
$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$
On substituting the values we get,
$$\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{2.5\Omega }+\frac{1}{2.5\Omega } \\ \frac{1}{R_{eq}}=\frac{2}{2.5\Omega } \end{gathered}$$
R_eq=2.5 /2
R_eq=1.25 Ω
Thus, the net change in the resistance will be R_eq =1.25 Ω