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Question

If a cuboid of dimensions 10 cm × 15 cm × 5 cm is cut to form cubes of sides 5 cm, then what is the difference between the sum of the surface areas of these cubes and the surface area of the original cuboid?

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Solution

Given, dimensions of cuboid is 10 cm×15 cm ×5 cmSo, Surface area of cuboid=210×15+15×5+5×10 =2150+75+50 =2275 =550 cm2Now, cuboid is cut to form cubes of side 5 cm.Thus,Total number of cubes=Volume of cuboidVolume of each cube =10×15×55×5×5 =6Surface area of each cube=6a2=6×52=150 cm2So, Sum of all surface area of cubes=6×150=900 cm2Now, Difference between the sum of the surface area of cubes and surface area of cuboid=900 cm2-550 cm2=350 cm2Hence, Difference between the sum of the surface area of cubes and surface area of cuboid is 350 cm2.Given, dimensions of cuboid is 10 cm×15 cm ×5 cmSo, Surface area of cuboid=210×15+15×5+5×10 =2150+75+50 =2275 =550 cm2Now, cuboid is cut to form cubes of side 5 cm.Thus,Total number of cubes=Volume of cuboidVolume of each cube =10×15×55×5×5 =6Surface area of each cube=6a2=6×52=150 cm2So, Sum of all surface area of cubes=6×150=900 cm2Now, Difference between the sum of the surface area of cubes and surface area of cuboid=900 cm2-550 cm2=350 cm2Hence, Difference between the sum of the surface area of cubes and surface area of cuboid is 350 cm2.

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