Question

if a linear equation has solution (-3,3), (0,0),(-3,-3), than it is in the form of y-x=0. Comment.

Answer 1

$\begin{array}{l}(0,0)\text{and}(-3,-3)\text{satisfy the given equation}y-x=0.\\ \therefore (0,0)\text{and}(-3,-3)\text{are the solutions of the given equation}\text{.}\\ (-3,3)\text{does not satisfy the equation}\text{.}\\ \therefore \text{It is not a solution of the given equation}\text{.}\end{array}$