Answer :
Let our polynomial = f ( x )
By remainder theorem , we know
f ( 2 ) = 1 ( As remainder ) ------------------ ( 1 )
And
f ( 3 ) = 3 ( As remainder ) ------------------ ( 1 )
And let our remainder = ax + b when polynomial divide by ( x - 2 ) ( x - 3 )
So,
f ( x ) = q ( x ) ( x - 2 ) ( x - 3 ) + ax + b
At x = 2 , we get
f ( 2 ) = q ( 2 ) ( 2 - 2 ) ( 2 - 3 ) + 2a + b
Substitute value of f ( 2 ) from equation 1 , and get
2a + b = 1 ------------------- ( 3 )
Now ​At x = 3 , we get
f ( 3 ) = q ( 3 ) ( 3 - 2 ) ( 3 - 3 ) + 3a + b
Substitute value of f ( 3 ) from equation 2 , and get
3a + b = 3 ------------------- ( 4 )
Now we subtract equation 3 from equation 4 ,and get
a = 2 ( substitute that value in equation 3 , we get
2 ( 2 ) + b = 1
b = 1 - 4
b = - 3
SO,
Our remainder will be = 2x - 3 ( Ans )