If a stone is thrown vertically upwards to a height of 9.8 m , calculate
i) the velocity with which it was thrown and
ii) time taken by it to reach the highest point
take g=10m/s square

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Solution

Let, u be the initial velocity.
Using, v² = u² + 2as
=> 0 = u² + (2)(-10)(9.8) [velocity at maximum height is 0]
=> u = 14 m/s
Let, ‘t’ be the time taken to reach the maximum height.
Using, v = u + at
=> 0 = 14 + (-10)t
=> t = 1.4 s

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If a stone is thrown vertically upwards to a height of 9.8 m , calculatei) the velocity with which it was thrown andii) time taken by it to reach the highest pointtake g=10m/s square

Let, u be the initial velocity.Using, v2 = u2 + 2as=> 0 = u2 + (2)(-10)(9.8) [velocity at maximum height is 0]=> u = 14 m/sLet, ‘t’ be the time taken to reach the maximum height.Using, v = u + at=> 0 = 14 + (-10)t=> t = 1.4 s

If a stone is thrown vertically upwards to a height of 9.8 m , calculate
i) the velocity with which it was thrown and
ii) time taken by it to reach the highest point
take g=10m/s square

Let, u be the initial velocity.
Using, v² = u² + 2as
=> 0 = u² + (2)(-10)(9.8) [velocity at maximum height is 0]
=> u = 14 m/s
Let, ‘t’ be the time taken to reach the maximum height.
Using, v = u + at
=> 0 = 14 + (-10)t
=> t = 1.4 s