Question

if an electron proton possess same de-Broglie's wavelength velocity of electron V m/s then what will be the approx. velocity of proton.?

Answer 1

Given,
velocity of electron = V m/s
de Broglie Wavelength of electron = de Broglie wavelength of proton
Therefore,
$$\begin{gathered} \frac{h}{m_{e}V}=\frac{h}{m_{p}v}where{m}_{e}ismassofelectronand{m}_{p}ismassofproton \\ \frac{1}{9.1x{10}^{-31}KgxV}=\frac{1}{1.67x{10}^{-27}Kgxv} \\ v=5.45x{10}^{-4}xVm/s \end{gathered}$$