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Ionisation Energy

If Lattice en...

Question

If Lattice enthalpy and hydration enthalpy for 1 mole of NaCl are 788 KJmol^-1and-784 KJ mol^-1respectively then enthalpy of solution of NaCl(s)would be
(1)-4KJmol^-1
(2)+4KJmol^-1
(3)-8KJ mol^-1
(4)+8KJ mol^-1
Explain.

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Solution

H_hyd= H_lattice+ H_solv
-784 = 788 + H_solv
H_{solv =}-784 -(-788) = +4kJ

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