Dear Student!
If the question is “if n times the mth term is equal to m times the nth term, then what is (m + n)th term of the A.P.”, then the answer is given below.
Let the first term and common difference of the A.P. be ‘a’ and ‘d’ respectively.
Then, mth term = a + (m – 1) d and nth term = a + (n – 1) d
By the given condition,
n [a + (m – 1) d] = m [a + (n – 1) d]
⇒ na + n (m – 1) d = ma + m (n – 1) d
⇒ n(m – 1)d – m (n – 1)d = ma – na
⇒ d[n(m – 1) – m (n – 1)] = a (m – n)
⇒ d[nm – n – mn + m] = a (m – n)
⇒ d(m – n) = a (m – n)
⇒ d = a
Now (m + n)th term = a + (m + n – 1)d.
But d = a
∴ (m + n)th term = a + (m + n – 1) a = a + a(m + n) – a = a (m + n)
Best wishes!